Yesterday my younger son and I talked through this fun problem I learned from Pasquale Cirillo:
and Cirillo’s discussion of the problem is here:
Yesterday we did not get to the optimal solution, but rather looked at the strategy of stopping when you get a 6 on the first or second roll, and then at stopping when you get a 4 or higher on the first or second roll. I asked my son to think about the problem a bit more this morning while I was out and he was able to find the optimal solution.
Here’s what he did in his own words:
Next he showed how he used Mathematica to help him find the best solution:
Finally, I showed him an alternation approach to finding the optimal solution that comes from working backwards. This is the approach that Cirillo takes in his discussion of the problem: